Preflow-push with excess scaling: Difference between revisions
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== Correctness == | == Correctness == | ||
Whenever an iteration is finished, no excess of <math>\Delta/2</math> or more is left at any node. When the break condition applies, no excess is left at all. | Whenever an iteration is finished, no excess of <math>\Delta/2</math> or more is left at any node. When the break condition applies, no excess is left at all. Termination of the main loop follows from the following complexity considerations. | ||
== Complexity == | == Complexity == |
Revision as of 15:30, 10 November 2014
Abstract view
Algorithmic problem: max-flow problem (standard version)
Type of algorithm: a variation of the generic preflow-push algorithm.
Invariant: Before and after each iteration:
- All points of the invariant of the preflow-push algorithm.
- There is a nonnegative, integral value [math]\displaystyle{ \Delta }[/math], and the excess [math]\displaystyle{ e_f(v) }[/math] of no active node [math]\displaystyle{ v }[/math] exceeds [math]\displaystyle{ \Delta }[/math].
Variant: [math]\displaystyle{ \Delta }[/math] is divided by two (integral division).
Break condition: [math]\displaystyle{ \Delta=0 }[/math].
Induction basis
- All steps in the induction basis of the preflow push algorithm.
- Set [math]\displaystyle{ \Delta:=2^L }[/math], where [math]\displaystyle{ L:=\lceil\log_2U\rceil }[/math] and [math]\displaystyle{ U:=\max\{u(a)|a\in A\} }[/math].
Induction step
Abstract view: Run the preflow-push algorithm with two modifications:
- Ignore all active nodes whose excess is smaller than [math]\displaystyle{ \Delta/2 }[/math]. In particular, an iteration of the main loop is finished once no node has an excess of [math]\displaystyle{ \Delta/2 }[/math] or more.
- Among the nodes with excess at least [math]\displaystyle{ \Delta/2 }[/math], choose one with minimum [math]\displaystyle{ d }[/math]-label.
- Do not push more than [math]\displaystyle{ \Delta-e_f(w) }[/math] units of flow over an arc [math]\displaystyle{ (v,w) }[/math].
- At the end, set [math]\displaystyle{ \Delta:=\Delta/2 }[/math].
Proof: obvious.
Correctness
Whenever an iteration is finished, no excess of [math]\displaystyle{ \Delta/2 }[/math] or more is left at any node. When the break condition applies, no excess is left at all. Termination of the main loop follows from the following complexity considerations.