Binary search tree: find: Difference between revisions
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'''Invariant:''' After <math>i\geq 0</math> Iterations. | '''Invariant:''' After <math>i\geq 0</math> Iterations. | ||
# The pointer '''''p''''' points to a tree node '''''v''''' on height level '''''i''''' (or is void). | # The pointer '''''p''''' points to a tree node '''''v''''' on height level '''''i''''' (or is void). | ||
# The key '''''K''''' is in the [[Directed Tree#Ranges of Search Tree Nodes]] of '''''v'''''. | # The key '''''K''''' is in the [[Directed Tree#Ranges of Search Tree Nodes#range]] of '''''v'''''. | ||
'''Variant:''' '''''i''''' is increased by 1. | '''Variant:''' '''''i''''' is increased by 1. | ||
Revision as of 13:50, 9 May 2015
General Information
Algorithmic Problem: Sorted Sequence:find
Type of algorithm: loop
Auxiliary data: A pointer p of type "pointer to binary search tree node of type [math]\displaystyle{ \kappa }[/math]".
Abstract view
Invariant: After [math]\displaystyle{ i\geq 0 }[/math] Iterations.
- The pointer p points to a tree node v on height level i (or is void).
- The key K is in the Directed Tree#Ranges of Search Tree Nodes#range of v.
Variant: i is increased by 1.
Break condition: Either it is [math]\displaystyle{ p = void }[/math] or, otherwise, [math]\displaystyle{ p.key = K }[/math].
Induction basis
Abstract view: Set p:= root.
Implementation: Obvious
Proof: Nothing to show
Induction step
Abstract view: If p points to a node but not with key K, p descends in the appropriate direction, left or right.
Implementation:
- If [math]\displaystyle{ p = void }[/math], terminate the algorithm and return false.
- Otherwise, if [math]\displaystyle{ p.key = K }[/math], terminate the algorithm and return true.
- Otherwise:
- If [math]\displaystyle{ K \lt p.key }[/math], set [math]\displaystyle{ p := left }[/math].
- If [math]\displaystyle{ K \gt p.key }[/math], set [math]\displaystyle{ p := right }[/math].
Correctnes: Obvious.
Complexity
Statement: Linear in the length of the sequence in the worst case (more precisely, linear in the height of the tree).
Proof: Obvious.
Pseudocode
TREE-SEARCH (x, k)
- if x= NIL or k = key[x]
- then return x
- if k < key[x]
- then return TREE-SEARCH(left[x], k)
- else return TREE-SEARCH(right[x], k)