B-tree: find: Difference between revisions
Jump to navigation
Jump to search
Line 25: | Line 25: | ||
== Induction Step == | == Induction Step == | ||
'''Abstract view:''' | |||
# Let '''''N''''' denote the node to which '''''p''''' currently points. | |||
# If the searched key is in '''''N''''', terminate the algorithm and return '''''true'''''. | |||
# Otherwise, if '''''N''''' is a leaf, terminate the algorithm and return '''''false'''''. | |||
# Otherwise, let '''''p''''' point the child of '''''N''''' such that the searched key is in the [[Directed tree|range]] of that child | |||
'''Implementation:''' | |||
# If '''''K''''' is one of the values <math>p.keys[1],\dots,p.keys[p.n]</math>, terminate the algorithm and return '''''true'''''. | |||
# If <math>p.children[0] = void</math> (that is, the current node is a leaf), terminate the algorithm and return '''''false'''''. | |||
# If <math>K < p.keys[1]</math> set <math>p := p.children[p.n]</math>. | |||
# Otherwise, if <math>K > p.keys[p.n]</math set <math>p := p.children[p.n]</math>. | |||
# Otherwise, there is exactly one <math>i \in \{1,\dots,p.n-1\}</math> such that <math>p.keys[i] < K < p.keys[i+1]</math>. | |||
# Set <math>p := p.children[i]</math>. | |||
'''Correctness:''' Obvious. | |||
== Complexity == | == Complexity == |
Revision as of 22:13, 25 September 2014
General Information
Algorithmic problem: Sorted sequence: find
Type of algorithm: loop
Auxiliary data: A pointer p of type "pointer to a B-tree node".
Abstract View
Invariant: Before and after each iteration:
- p points to some node N of the B-tree and
- the searched key is in the range of N.
Variant: p is redirected from the current node N to some child of the current node.
Break condition:
- p points to a leaf of the B-tree or (that is, inclusive-or)
- the searched key is in the node to which p points.
Induction Basis
Abstract view: p is initialized so as to point to the root of the B-tree.
Implementation: Obvious.
Proof: Obvious.
Induction Step
Abstract view:
- Let N denote the node to which p currently points.
- If the searched key is in N, terminate the algorithm and return true.
- Otherwise, if N is a leaf, terminate the algorithm and return false.
- Otherwise, let p point the child of N such that the searched key is in the range of that child
Implementation:
- If K is one of the values [math]\displaystyle{ p.keys[1],\dots,p.keys[p.n] }[/math], terminate the algorithm and return true.
- If [math]\displaystyle{ p.children[0] = void }[/math] (that is, the current node is a leaf), terminate the algorithm and return false.
- If [math]\displaystyle{ K \lt p.keys[1] }[/math] set [math]\displaystyle{ p := p.children[p.n] }[/math].
- Otherwise, if [math]\displaystyle{ K \gt p.keys[p.n]\lt /math set \lt math\gt p := p.children[p.n] }[/math].
- Otherwise, there is exactly one [math]\displaystyle{ i \in \{1,\dots,p.n-1\} }[/math] such that [math]\displaystyle{ p.keys[i] \lt K \lt p.keys[i+1] }[/math].
- Set [math]\displaystyle{ p := p.children[i] }[/math].
Correctness: Obvious.