Binary search tree: insert: Difference between revisions
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== Induction Basis == | == Induction Basis == | ||
'''Abstract view:''' If the tree is empty, a new root with key '''''K''''' is created; otherwise, '''''p''''' is initialized so as to point to the root. | |||
'''Implementation:''' | |||
# If <math>root = void</math> | |||
## Create a new binary search tree node and let '''''root''''' point to it. | |||
## Set <math>root.key := K, root.left := void</math>. and <math>root.right := void</math>. | |||
# Otherwise, set <math>p := root<math>. | |||
'''Proof:''' Obvious. | |||
== Induction Step == | == Induction Step == |
Revision as of 19:38, 25 September 2014
General Information
Algorithmic problem: Sorted sequence: insert
Type of algorithm: loop
Auxiliary data: A pointer p of type "pointer to binary search tree node of type [math]\displaystyle{ \kappa }[/math]".
Abstract View
Invariant: After [math]\displaystyle{ i \geq 0 }[/math] iterations:
- The pointer p points to a tree node v on height level i.
- The Key K is in the range of v.
Variant: i increased by 1.
Break condition: One of the following two conditions is fulfilled:
- It is [math]\displaystyle{ p.key \geq K }[/math] and [math]\displaystyle{ p.left = void }[/math].
- It is [math]\displaystyle{ p.key \leq K }[/math] and [math]\displaystyle{ p.right = void }[/math].
Induction Basis
Abstract view: If the tree is empty, a new root with key K is created; otherwise, p is initialized so as to point to the root.
Implementation:
- If [math]\displaystyle{ root = void }[/math]
- Create a new binary search tree node and let root point to it.
- Set [math]\displaystyle{ root.key := K, root.left := void }[/math]. and [math]\displaystyle{ root.right := void }[/math].
- Otherwise, set <math>p := root<math>.
Proof: Obvious.
Induction Step
Copmplexity
Pseudocode
TREE-INSERT(T, z)
- y = Null
- x = root(T)
- while x ≠ NULL
- y = x
- if key[z] < key[x]
- then x = left[x]
- then x = right[x]
- p[z] = y
- if y = NULL
- then root[T] = z //Tree was empty
- else if key[z] < key[y]
- then left[y] = z
- else right[y] = z