Binary search tree: find: Difference between revisions
Line 35: | Line 35: | ||
'''Implementation:''' | '''Implementation:''' | ||
# If <math>p = | # If <math>p =</math>void, terminate the algorithm and return ''''false''''. | ||
# Otherwise, if <math>p.key = K</math>, terminate the algorithm and return | # Otherwise, if <math>p</math>.key <math>= K</math>, terminate the algorithm and return ''''true''''. | ||
# Otherwise: | # Otherwise: | ||
## If <math>K < p | ## If <math>K < p</math>.key, set <math>p :=</math>left. | ||
## If <math>K > p | ## If <math>K > p</math>.key, set <math>p :=</math> right. | ||
'''Correctnes:''' Obvious. | '''Correctnes:''' Obvious. |
Revision as of 09:33, 17 May 2015
General Information
Algorithmic Problem: Sorted Sequence:find
Type of algorithm: loop
Auxiliary data: A pointer [math]\displaystyle{ p }[/math] of type "pointer to binary search tree node of type [math]\displaystyle{ \mathcal{K} }[/math]."
Abstract view
Invariant: After [math]\displaystyle{ i\geq 0 }[/math] Iterations.
- The pointer [math]\displaystyle{ p }[/math] points to a tree node [math]\displaystyle{ v }[/math] on height level [math]\displaystyle{ i }[/math] (or is void).
- The key [math]\displaystyle{ K }[/math] is in the range of [math]\displaystyle{ v }[/math].
Variant: [math]\displaystyle{ i }[/math] is increased by 1.
Break condition: Either it is [math]\displaystyle{ p = }[/math]void or, otherwise, it is[math]\displaystyle{ p }[/math].key [math]\displaystyle{ = K }[/math].
Induction basis
Abstract view: Set [math]\displaystyle{ p:= }[/math] root.
Implementation: Obvious
Proof: Nothing to show
Induction step
Abstract view: If p points to a node but not with key K, p descends in the appropriate direction, left or right.
Implementation:
- If [math]\displaystyle{ p = }[/math]void, terminate the algorithm and return 'false'.
- Otherwise, if [math]\displaystyle{ p }[/math].key [math]\displaystyle{ = K }[/math], terminate the algorithm and return 'true'.
- Otherwise:
- If [math]\displaystyle{ K \lt p }[/math].key, set [math]\displaystyle{ p := }[/math]left.
- If [math]\displaystyle{ K \gt p }[/math].key, set [math]\displaystyle{ p := }[/math] right.
Correctnes: Obvious.
Complexity
Statement: Linear in the length of the sequence in the worst case (more precisely, linear in the height of the tree).
Proof: Obvious.
Pseudocode
TREE-SEARCH (x, k)
- if x= NIL or k = key[x]
- then return x
- if k < key[x]
- then return TREE-SEARCH(left[x], k)
- else return TREE-SEARCH(right[x], k)