Binary search tree: find

Binary Search Tree
Find

Sorted sequence

Openlearnware
See Chapter 2,3

General Information

Algorithmic Problem: Sorted Sequence:find

Type of algorithm: loop

Auxiliary data: A pointer [math]\displaystyle{ p }[/math] of type "pointer to binary search tree node of type [math]\displaystyle{ \mathcal{K} }[/math]."

Abstract view

Invariant: After [math]\displaystyle{ i\geq 0 }[/math] Iterations.

1. The pointer [math]\displaystyle{ p }[/math] points to a tree node [math]\displaystyle{ v }[/math] on height level [math]\displaystyle{ i }[/math] (or is void).
2. The key [math]\displaystyle{ K }[/math] is in the range of [math]\displaystyle{ v }[/math].

Variant: [math]\displaystyle{ i }[/math] is increased by 1.

Break condition: Either it is [math]\displaystyle{ p = }[/math]void or, otherwise, it is[math]\displaystyle{ p }[/math].key [math]\displaystyle{ = K }[/math].

Induction basis

Abstract view: Set p:= root.

Implementation: Obvious

Proof: Nothing to show

Induction step

Abstract view: If p points to a node but not with key K, p descends in the appropriate direction, left or right.

Implementation:

1. If [math]\displaystyle{ p = void }[/math], terminate the algorithm and return false.
2. Otherwise, if [math]\displaystyle{ p.key = K }[/math], terminate the algorithm and return true.
3. Otherwise:
   1. If [math]\displaystyle{ K \lt p.key }[/math], set [math]\displaystyle{ p := left }[/math].
   2. If [math]\displaystyle{ K \gt p.key }[/math], set [math]\displaystyle{ p := right }[/math].

Correctnes: Obvious.

Complexity

Statement: Linear in the length of the sequence in the worst case (more precisely, linear in the height of the tree).

Worst case binary search tree

Proof: Obvious.

Pseudocode

TREE-SEARCH (x, k)

if x= NIL or k = key[x]

then return x

if k < key[x]

then return TREE-SEARCH(left[x], k)

else return TREE-SEARCH(right[x], k)