B-tree: find: Difference between revisions

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'''Correctness:''' Obvious.
'''Correctness:''' Obvious.
== Pseudocode ==
<code>
B-TREE(''x,k'')
1 ''i'' = 1
2 '''while''' i &le; ''x.n'' and ''k'' &gt; ''x.key<sub>i</sub>''
3        ''i'' = ''i'' + 1
4 '''if''' ''i'' &le; ''x.n'' and ''k'' == ''x.key<sub>i</sub>''
5        '''return''' (''x.i'')
6 '''elseif''' '' x.leaf''
7        '''return''' NIL
8 '''else''' DISK-READ(''x.c<sub>i</sub>'')
9        '''return''' B-TREE-FIND(''x.c<sub>i</sub>,k'')
</code>


== Complexity ==
== Complexity ==

Revision as of 16:15, 30 September 2014

General Information

Algorithmic problem: Sorted sequence: find

Type of algorithm: loop

Auxiliary data: A pointer p of type "pointer to a B-tree node".

Abstract View

Invariant: Before and after each iteration:

  1. p points to some node N of the B-tree and
  2. the searched key is in the range of N.

Variant: p is redirected from the current node N to some child of the current node.

Break condition:

  1. p points to a leaf of the B-tree or (that is, inclusive-or)
  2. the searched key is in the node to which p points.

Induction Basis

Abstract view: p is initialized so as to point to the root of the B-tree.

Implementation: Obvious.

Proof: Obvious.

Induction Step

Abstract view:

  1. Let N denote the node to which p currently points.
  2. If the searched key is in N, terminate the algorithm and return true.
  3. Otherwise, if N is a leaf, terminate the algorithm and return false.
  4. Otherwise, let p point the child of N such that the searched key is in the range of that child

Implementation:

  1. If K is one of the values [math]\displaystyle{ p.keys[1],\dots,p.keys[p.n] }[/math], terminate the algorithm and return true.
  2. If [math]\displaystyle{ p.children[0] = void }[/math] (that is, the current node is a leaf), terminate the algorithm and return false.
  3. If [math]\displaystyle{ K \lt p.keys[1] }[/math] set [math]\displaystyle{ p := p.children[p.n] }[/math].
  4. Otherwise, if [math]\displaystyle{ K \gt p.keys[p.n]\lt /math set \lt math\gt p := p.children[p.n] }[/math].
  5. Otherwise, there is exactly one [math]\displaystyle{ i \in \{1,\dots,p.n-1\} }[/math] such that [math]\displaystyle{ p.keys[i] \lt K \lt p.keys[i+1] }[/math].
  6. Set [math]\displaystyle{ p := p.children[i] }[/math].

Correctness: Obvious.

Pseudocode

B-TREE(x,k)
1 i = 1
2 while i ≤ x.n and k > x.keyi 
3        i = i + 1
4 if ix.n and k == x.keyi 
5        return (x.i)
6 elseif  x.leaf
7        return NIL
8 else DISK-READ(x.ci) 
9        return B-TREE-FIND(x.ci,k)


Complexity

Statement: The asymptotic complexity is in [math]\displaystyle{ \Theta(\log n) }[/math] in the worst case.

Proof: Follows immediately from the fact that the height of B-tree with n nodes is in [math]\displaystyle{ \Theta(\log n) }[/math] (cf. the remark clause of the B-Trees page).